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Q. In the following reaction, rate constant is $1.2 \times 10^{-2} M s ^{-1} A \longrightarrow B$. What is concentration of $B$ after $10 \,min .$, if we start with $10 \,M$ of $A$.

Chemical Kinetics

Solution:

It is zero order reaction
$x=k t $
$x=1.2 \times 10^{-2} \times(10 \times 60) $
$x=7.2 \,M$