Question

In the following reaction,
$ N{{H}_{3}}+B{{F}_{3}}\xrightarrow[{}]{{}}N{{H}_{3}}\to B{{F}_{3}} $
which behaves like Lewis base?

• A. $ N{{H}_{3}} $
• B. $ B{{F}_{3}} $
• C. $ N{{H}_{3}}\to B{{F}_{3}} $
• D. None of these

Answer 1

Answer: (A)

According to Lewis concept, Lewis base is electron pair donor and Lewis acid is electron pair acceptor. Hence, $ N{{H}_{3}} $ behaves as Lewis base and $ B{{F}_{3}} $ as Lewis acid.
$ \underset{donor}{\mathop{{{H}_{3}}N_{\bullet }^{\bullet }}}\,+\underset{acceptor}{\mathop{B{{F}_{3}}}}\,\xrightarrow[{}]{{}}{{H}_{3}}N\xrightarrow[{}]{{}}B{{F}_{3}} $