Question

In the following reaction, $C_2H_2 \xrightarrow[{HgSO_4/H_2SO_4, 60^{\circ}C}]{H_2O} X \rightleftharpoons CH_3CHO$
What is $X ?$

• A. $CH _{3} CH _{2} OH$
• B. $CH _{3}- O - CH _{3}$
• C. $CH _{3} CH _{2} CHO$
• D. $CH _{2}= CHOH$

Answer 1

Answer: (D)

Correct answer is (d) $CH _{2}= CHOH$