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Q. In the following reaction:
$3Fe + 4H_2O\to Fe_3O_4 + 4H_2,$ if the atomic weight of iron is $56$, then its equivalent weight will be

Some Basic Concepts of Chemistry

Solution:

$3Fe+4H_{2}O\to Fe_{3}O_{4}+4H_{2}$
$3Fe+4H_{2}O\to Fe_{3}O_{4}+8H^{+}+8e^{-}$
$V.F.$ of $Fe=\frac{8}{3}$
$E_{Fe}=\frac{\text{Atomic mass}}{V.F} =\frac {56}{8/3}=21$