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Q. In the following observation.
Acid $K _{a_{1}}$ $K _{a_{2}}$ $(X)$
Oxalic acid $5.9 \times 10^{-2}$ $6.4 \times 10^{-5}$
Ascorbic acid $7.4 \times 10^{-4}$ $1.6 \times 10^{-12}$
Sulphurous acid $1.7 \times 10^{-2}$ $6.4 \times 10^{-8}$
$(Y)$ Very large $1.2 \times 10^{-2}$
Carbonic acid $4.3 \times 10^{-7}$ $(Z)$
Citric acid $7.4 \times 10^{-4}$ $1.7 \times 10^{-5}$ $4.0 \times 10^{-7}$
Phosphoric acid $7.5 \times 10^{-3}$ $6.2 \times 10^{-8}$ $4.2 \times 10^{-13}$

$X, Y$ and $Z$ respectively are

Equilibrium

Solution:

Correct answer is (d) $K_{a_{3}}$, sulphuric acid, $5.6 \times 10^{-11}$