Q.
In the following observation.
Acid
$K _{a_{1}}$
$K _{a_{2}}$
$(X)$
Oxalic acid
$5.9 \times 10^{-2}$
$6.4 \times 10^{-5}$
Ascorbic acid
$7.4 \times 10^{-4}$
$1.6 \times 10^{-12}$
Sulphurous acid
$1.7 \times 10^{-2}$
$6.4 \times 10^{-8}$
$(Y)$
Very large
$1.2 \times 10^{-2}$
Carbonic acid
$4.3 \times 10^{-7}$
$(Z)$
Citric acid
$7.4 \times 10^{-4}$
$1.7 \times 10^{-5}$
$4.0 \times 10^{-7}$
Phosphoric acid
$7.5 \times 10^{-3}$
$6.2 \times 10^{-8}$
$4.2 \times 10^{-13}$
$X, Y$ and $Z$ respectively are
Acid | $K _{a_{1}}$ | $K _{a_{2}}$ | $(X)$ |
---|---|---|---|
Oxalic acid | $5.9 \times 10^{-2}$ | $6.4 \times 10^{-5}$ | |
Ascorbic acid | $7.4 \times 10^{-4}$ | $1.6 \times 10^{-12}$ | |
Sulphurous acid | $1.7 \times 10^{-2}$ | $6.4 \times 10^{-8}$ | |
$(Y)$ | Very large | $1.2 \times 10^{-2}$ | |
Carbonic acid | $4.3 \times 10^{-7}$ | $(Z)$ | |
Citric acid | $7.4 \times 10^{-4}$ | $1.7 \times 10^{-5}$ | $4.0 \times 10^{-7}$ |
Phosphoric acid | $7.5 \times 10^{-3}$ | $6.2 \times 10^{-8}$ | $4.2 \times 10^{-13}$ |
Equilibrium
Solution: