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Q. In the following nuclear rection,
$D \xrightarrow {\alpha} D _{1} \xrightarrow {\beta^{-}} D _{2} \xrightarrow {\alpha} D _{3} \xrightarrow {\gamma} D _{4}$
Mass number of D is $182$ and atomic number is $74 .$
Mass number and atomic number of $D _{4}$ respectively will be

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Solution:

Say for $D _{4}$ Atomic $No = Z$
Mass Number $=$ A
$A =182-4-4=174$
$Z =74-2+1-2=71$