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Q. In the following network, the current flowing through $15 \, \Omega \, $ resistance is
Question

NTA AbhyasNTA Abhyas 2022

Solution:

Solution
$I_{1} + I_{2} = 2.1 A$ ….(1)
$18 I_{1} = 24 I_{2}$ …(2)
$\Rightarrow $ $3 I_{1} = 4 I_{2} = 4 \left(\right. 2.1 - I_{1} \left.\right)$
$I_{1} = \frac{8.4}{7} = 1.2 A$