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Q. In the following figure, an object of mass $ 1.2\, kg $ is at rest at point $ P $ . lf $ R $ and $ F $ are the reaction and the frictional force, respectively, thenPhysics Question Image

AMUAMU 2011Laws of Motion

Solution:

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Given, $ m = 1.2 \,kg$
$R = mg\,\cos\,30^{\circ}$
$ = 1.2 \times 10 \times \frac{\sqrt{3}}{2}$
$R = (6\sqrt{3})N$
$f = mg\,\sin\,30^{\circ}$
$ = 1.2 \times 10 \times\frac{1}{2}$
$F = 6$