Question

In the following dehydration reaction the hybridised state of carbon changes $ C{{H}_{3}}CON{{H}_{2}}\xrightarrow[{}]{{{P}_{2}}{{O}_{5}}}C{{H}_{3}}CN+{{H}_{2}}O $

• A. $ s{{p}^{3}} $ to $ s{{p}^{2}} $
• B. $ sp $ to $ s{{p}^{2}} $
• C. $ s{{p}^{2}} $ to $ sp $
• D. $ sp $ to $ s{{p}^{3}} $

Answer 1

Answer: (C)

$ \underset{s{{p}^{2}}}{\mathop{C{{H}_{3}}-\overset{\begin{smallmatrix} O \\ || \end{smallmatrix}}{\mathop{C}}\,-N{{H}_{2}}}}\,\xrightarrow[{}]{{{P}_{2}}{{O}_{5}}}\underset{sp}{\mathop{C{{H}_{3}}-C\equiv N}}\,+{{H}_{2}}O $ In the above dehydration reaction the hybridised state of carbon is changing from $ s{{p}^{2}} $ tosp.