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Q. In the following common emitter configuration, an $N P N$ transistor with current gain $\beta=100$ is used. The output voltage of the amplifier will bePhysics Question Image

Semiconductor Electronics: Materials Devices and Simple Circuits

Solution:

Voltage gain $=\frac{\text { Output voltage }}{\text { Input voltage }}$
$\Rightarrow V_{\text {out }}=V_{\text {in }} \times$ Voltage gain
$\Rightarrow V_{\text {out }}=V_{\text {in }} \times$ Current gain $\times$ Resistance gain
$\Rightarrow V_{\text {out }}=V_{\text {in }} \times \beta \times \frac{R_{L}}{R_{B E}}$
$=10^{-3} \times 100 \times \frac{10}{1}$
$=1\, V$