Question

In the following circuit $i_{1}$ and $i_{2}$ are respectively (diodes are ideal)

• A. $0$ , $0$
• B. $5\,mA, 0$
• C. $0,5\,mA$
• D. $5\,mA$ , $5\,mA$

Answer 1

Answer: (B)

As the diodes are in forward bias condition, they will behave as a short-circuit.
So, there will not be any current through $14\,k\Omega $ and $12\,k\Omega $ resistors.

Therefore, $i_{1}=0\,A$
and $i_{2}=i=\frac{10\, V}{2\, k\Omega }=5\,mA$