Question

In the figure, three capacitors each of capacitance $6\, pF$ are connected in series. The total capacitance of the combination will be

• A. $9 \times 10^{-12} F$
• B. $6 \times 10^{-12} F$
• C. $3 \times 10^{-12} F$
• D. $2 \times 10^{-12} F$

Answer 1

Answer: (D)

$C'=C / n=\frac{6 \times 10^{-12}}{3}=2 \times 10^{-12} F$