Q.
In the figure, the equivalent capacitance between A and B is
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Solution:
The circuit can be simplified as shown.
It is a balanced Wheatstone bridge. $ \Rightarrow $ $ {{C}_{AB}}=\frac{5\times 3}{5+3}+\frac{5\times 3}{5+3} $ $ \Rightarrow $ $ {{C}_{AB}}=2\times \frac{15}{8}=\frac{30}{8}=3.75\,\mu F $