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  4. In the figure shown, what is the current (in Ampere) drawn from the battery ? You are given: R1 = 15 Ω, R2 = 10 Ω , R3 = 20 Ω, R4 = 5 Ω , R5 = 25 Ω, R6 = 30 Ω, E = 15 V

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Q. In the figure shown, what is the current (in Ampere) drawn from the battery ? You are given:
$R_1 = 15 \Omega, R_2 = 10 \Omega , R_3 = 20 \Omega, R_4 = 5 \Omega , R_5 = 25 \Omega, R_6 = 30 \Omega, E = 15 V$Physics Question Image

JEE MainJEE Main 2019Current Electricity

Solution:

$R_{eq} = 15+ \frac{25}{3} + 30 = \frac{45+25+90}{3} = \frac{160}{3}$
$ I = \frac{E}{R_{eq}} = \frac{15\times3}{160} = \frac{9}{32} amp $

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