Question

In the figure shown, the normal reaction between $2\, kg$ and $1\, kg$ is $\alpha$ newton and normal reaction between $3 \,kg$ and $2 \,kg$ is $\beta$ newton.Find $(\alpha+\beta) .\left(g=10 \,m / s ^{2}\right)$.

Answer 1

$a=\frac{60-(18+30)}{6}=2 \,m / s ^{2}$

So, all the three blocks will accelerate upwards with $a=2 \,m / s ^{2}$.
$N_{1}(18+5)= 1 \times 2$
$N_{1}=25 N$

$N_{2}-(18+15)=3 \times 2$
$N_{2}=39 N$