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Q.
In the figure shown, the magnetic field induction at the point $O$ will be
ManipalManipal 2010Electromagnetic Induction
Solution:
Field due to a straight wire of infinite length is $\frac{\mu_{0}^{i}}{4 \pi r}$ if the point is on a line perpendicular to its length while at the centre of a semicircular coil is $\frac{\mu_{0} \pi i}{4 \pi r}$.
$\therefore B=B_{a}+B_{b}+B_{c}$
$=\frac{\mu_{0}}{4 \pi} \frac{i}{r}+\frac{\mu_{0}}{4 \pi} \frac{\pi i}{r}+\frac{\mu_{0}}{4 \pi-} \frac{i}{x}$
$=\frac{\mu_{0}}{4 \pi} \frac{i}{r}(\pi+2)$ out of the page