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Q. In the figure shown initially spring is in unstretched state and blocks are at rest. Now $100\, N$ force is applied on block A and B as shown in figure. After some time velocity of ‘A’ becomes 2 m/s and that of ‘ B ‘ $4\, m/s$ and blocks displaced by amount $10\, cm$ and spring is stretched by amount $30\, cm$. Then work done by spring force on A will be:
image

Work, Energy and Power

Solution:

$W_{\text {spring }}+W_{100\, N }=\Delta k$ (on A)
$W_{\text {spring }}+(100)\left(\frac{10}{100}\right)=\frac{1}{2}(2)(2)^{2}$
$W_{\text {spring }}=4-10=-6\, J$