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  4. In the figure shown an ideal liquid is flowing through the tube which is of uniform area of cross-section. The liquid has velocities vA and vB, and pressures PA and PB at points A and B respectively. Then <img class=img-fluid question-image alt=image src=https://cdn.tardigrade.in/img/question/physics/1b9281afe55d3c573c8d7b28fd4f1c66-.png />

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Q. In the figure shown an ideal liquid is flowing through the tube which is of uniform area of cross-section. The liquid has velocities $v_{A}$ and $v_{B}$, and pressures $P_{A}$ and $P_{B}$ at points $A$ and $B$ respectively. Then
image

Mechanical Properties of Fluids

Solution:

For a streamline flow of an ideal liquid, $v_{A} = v_{B}$. The pressure at $B =$ pressure at $A +$ pressure due to column of liquid of height $AB$