Question

In the figure shown an ideal liquid is flowing through the tube which is of uniform area of cross-section. The liquid has velocities $v_{A}$ and $v_{B}$, and pressures $P_{A}$ and $P_{B}$ at points $A$ and $B$ respectively. Then

• A. $v_{B} > \, v_{A}$
• B. $v_{B} = v_{A}$
• C. $P_{B} < \, P_{A}$
• D. $P_{B} = P_{A}$

Answer 1

Answer: (B)

For a streamline flow of an ideal liquid, $v_{A} = v_{B}$. The pressure at $B =$ pressure at $A +$ pressure due to column of liquid of height $AB$