Question

In the figure shown, a point object $O$ is placed in air. A spherical boundary of radius of curvature $1.0\, m$ separates various media. $A B$ is the principal axis. The refractive index above $A B$ is $1.6$ and below $A B$ is $2.0$. The separation (in m) between the images formed due to refraction at spherical surface is

Answer 1

$I_{1} \Rightarrow \frac{1.6}{v}-\frac{1}{-2}=\frac{1.6-1}{+1} $
$\Rightarrow v_{1}=16$
$I_{2} \Rightarrow \frac{2.0}{v}-\frac{1}{-2}=\frac{2-1}{1} $
$\Rightarrow v_{2}=4$
$\left|v_{1}-v_{2}\right|=12\, m$