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  4. In the figure shown a current I1 is established in the long straight wire AB. Another wire CD carrying current I2 is placed in the plane of the paper. The line joining the ends of the wire is perpendicular to the wire AB. The resultant force on the wire CD is: <img class=img-fluid question-image alt=Question src=https://cdn.tardigrade.in/q/nta/p-awaijyle7oax.png />

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Q. In the figure shown a current I1 is established in the long straight wire AB. Another wire CD carrying current I2 is placed in the plane of the paper. The line joining the ends of the wire is perpendicular to the wire AB. The resultant force on the wire CD is :

Question

NTA AbhyasNTA Abhyas 2020Moving Charges and Magnetism

Solution:

Diagram of force acting on wire will be as shown in diagram
Solution
but magnitude of all elemental forces are not equal and not even symmetrically distributed so no componentof force will get canceled completely so resultant, will have component in x as well as y