Q.
In the figure shown, a circuit contains two identical resistors with resistance $R = 5\Omega$ and an inductance with $L = 2mH$. An ideal battery of $15 V$ is connected in the circuit. What will be the current through the battery long after the switch is closed?
Solution:
Ideal inductor will behave like zero resistance long time after switch is closed
$I = \frac{2\varepsilon}{R} = \frac{2\times15}{5} = 6A $
