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Q.
In the figure given, the value of $X$ resistance when the potential differences between $B$ and $D$ is zero, is
Current Electricity
Solution:
Potential difference between $B$ and $D$ is zero, it means Wheatstone bridge is in balanced condition.
So $\frac{P}{Q}=\frac{R}{S} $
$\Rightarrow \frac{21}{3+\frac{8 X}{(8+X)}}=\frac{18}{6} $
$\Rightarrow X=8\, \Omega$