Question

In the equation
${ }_{13}^{27} Al +{ }_{2}^{4} He \longrightarrow { }_{15}^{30} P + X$
The correct symbol for $X$ is

• A. ${ }_{-1}^{0}$
• B. ${ }_{1}^{1} H$
• C. ${ }_{2}^{4} He$
• D. ${ }_{0}^{1} n$

Answer 1

Answer: (D)

Conserving mass and charge, net mass reduces by $1$ by charge does not change.
Hence, a neutron must have been released.