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Chemistry
In the electrolysis of dilute H2SO4 using platinum electrode
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Q. In the electrolysis of dilute $H_2SO_4$ using platinum electrode
Electrochemistry
A
$H_2$ is liberated at cathode
56%
B
$O_2$ is produced at cathode
20%
C
$Cl_2$ is obtained at cathode
14%
D
$NH_3$ is produced at anode
10%
Solution:
$H_2$ is liberated at Cathode while $O_2$ is liberated at anode.