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Q. In the electric circuit shown each cell has an emf of, $ 2V $ and internal resistance of $ 1\,\Omega $ . The external resistance is $ 2\,\Omega $ . The value of the current $ I $ is: (in amperes):Physics Question Image

KEAMKEAM 2004Current Electricity

Solution:

$ Currents=\frac{net\,emf}{net\text{ }resistance} $ Or
$ I=\frac{2+2+2}{1+1+1+2}=\frac{6}{5}=1.2 \,A $