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  4. In the diagram 100 kg block is hanging from a pulley and force F is applied on the string to keep the system in equilibrium. If the whole system is moving up with a constant velocity v, then tension at point P in the string will be

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Q. In the diagram $100 \,kg$ block is hanging from a pulley and force $F$ is applied on the string to keep the system in equilibrium. If the whole system is moving up with a constant velocity $v$, then tension at point $P$ in the string will bePhysics Question Image

AIIMSAIIMS 2018Laws of Motion

Solution:

Tension in each part of the string will be F. Assume tension at point P is T.
T = 3F
2F = mg
2F = 100 × 9.8 N
F = 490 N
$\therefore \quad$ T = 3 × 490 = 1470 N

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