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Tardigrade
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Chemistry
In the correct H - C ≡ CH xrightarrow[ (2) CH3 CH2 Br](1) NaNH2 / liq.NH3X xrightarrow[ (2) CH3 CH2 Br](1) NaNH2 / liq.NH3 X and Y are :
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Q. In the correct $ H - C \equiv CH \xrightarrow[ (2) CH_3 CH_2 Br]{(1) NaNH_2 / liq.NH_3}X \xrightarrow[ (2) CH_3 CH_2 Br]{(1) NaNH_2 / liq.NH_3}$ X and Y are :
NEET
NEET 2016
Hydrocarbons
A
X = 2-Butyne ; Y=3-Hexyne
22%
B
X = 2-Butyne ; y=2-Hexyne
19%
C
X = 1-Butyne; y = 2-Hexyne
28%
D
X = 1-Butyne ; Y = 3-Hexyne
31%
Solution:
Correct answer is (d) X = 1-Butyne ; Y = 3-Hexyne