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  4. In the conversion of Br2 to BrO3-, the oxidation number of Br changes from

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Q. In the conversion of $ B{{r}_{2}} $ to $ BrO_{3}^{-}, $ the oxidation number of Br changes from

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Solution:

Bromine has zero oxidation state because it is in free state $ \overset{0}{\mathop{B{{r}_{2}}}}\,\xrightarrow{{}}BrO_{3}^{-} $ $ BrO_{3}^{-} $ $ x+(-2\times 3)=-1 $ $ x+(-\,6)=-1 $ $ x=+\,6-1 $ $ =+\,5 $ So, oxidation number changes from 0 to + 5.