Thank you for reporting, we will resolve it shortly
Q.
In the compounds $KMnO_4$ and $K_2Cr_2O_7$ the highest oxidation state is of the element :
Redox Reactions
Solution:
In $KMnO _{4}, K$ is in $+1$ oxidation state, $O$ is in $-2$ oxidation state $Mn$ is present in $+7$ oxidation state. In $K _{2} Cr _{2} O _{7}, K$ is in $+1$ oxidation state, $O$ is in $-2$ oxidation state Cr is present in $+6$ oxidation state. So $Mn$ is present in highest oxidation state.