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Q.
In the complex $[(Ni(H_2O)_2(NH_3)_4]^{2+}$ the number of unpaired electrons is
Coordination Compounds
Solution:
In the complex $\left[ Ni ( H 2 O )_{2}\left( NH _{3}\right)_{4}\right]^{2+}$ the $Ni$ is in $+2$ oxidation state and there are 8 electrons in $3 d$ subshell and since the $NH _{3}$ is a strong field ligand therefore the two unpaired electrons left gets paired up and hence the number of unpaired electrons become o. hence the magnetic moment $\sqrt{ n ( n +2)}$ where $n$ is the number of unpaired electron comes out to be o. Hence the correct