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  4. In the circuit shown the value of I in ampere is

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Q. In the circuit shown the value of I in ampere isPhysics Question Image

JamiaJamia 2008

Solution:

We can simplify the network as shown
So, net resistance, $ R=2.4+1.6=4.3 $ Therefore, current from the battery, $ i=\frac{V}{R}=\frac{4}{4}=1A $ Now from the circuit , $ 4I=6I $ $ \Rightarrow $ $ I=\frac{3}{2}I $ But $ i=I+I=I+\frac{3}{2}I=\frac{5}{2}I $ $ \therefore $ $ 1=\frac{5}{2}I $ $ \Rightarrow $ $ I=\frac{2}{5}=0.4\,A $

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