Thank you for reporting, we will resolve it shortly
Q.
In the circuit shown, the reading of the ammeter if diode is not ideal is
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Solution:
$I=\frac{3\,V}{200\,\Omega}=15\,mA$
If diode is not ideal, it also has resistance then reading will be slightly less than $15 \,mA$, if it is ideal then it will be $15\, mA$.