Question

In the circuit shown, the currents $i_1$ and $i_2$ are

• A. $i_1 = 1.5 A,\, i_2 = 0.5 A$
• B. $i_1 = 0.5 A,\, i_2 = 1.5 A$
• C. $i_1 = 1 A,\, i_2 = 3 A$
• D. $i = 3 A,\, i_2 = 1 A$

Answer 1

Answer: (B)

Resistance $R=\frac{12 \times 4}{12+4}+2=\frac{48}{16}+2=5\, \Omega$
Electric current $I=\frac{E}{R+r}=\frac{12}{6}=2 A$
$I_{1}+I_{2}=2 A$
$I \propto \frac{1}{R}$
$\therefore I_{2}=1.5 A , I_{1}=0.5\, A$