Thank you for reporting, we will resolve it shortly
Q.
In the circuit shown, the current through the ideal diode is
NTA AbhyasNTA Abhyas 2020Semiconductor Electronics: Materials Devices and Simple Circuits
Solution:
Ideal junction in forward bias behaves like a conducting wire.
$\therefore $ Current from the battery
$i=\frac{2}{80}=25 \, mA$
This current goes from diode as it behaves as short circuit.
