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  4. In the circuit shown, the average power dissipated in the resistor is (assume diode to be ideal)

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Q. In the circuit shown, the average power dissipated in the resistor is (assume diode to be ideal)Physics Question Image

Semiconductor Electronics: Materials Devices and Simple Circuits

Solution:

It's a half wave rectification $E_{\text {rms }}=\frac{E_{0}}{2}$
$P_{a v} =\frac{\left(E_{\text {rms }}\right)^{2}}{R} $
$=\frac{E_{0}^{2}}{4 R}$