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Question
Physics
In the circuit shown in the figure the potential difference between X and Y will be
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Q. In the circuit shown in the figure the potential difference between $X$ and $Y$ will be
AFMC
AFMC 2007
A
zero
B
20 V
C
60 V
D
120 V
Solution:
As circuit is open, therefore no current flows through circuit. Hence, potential difference across $X$ and $Y=$ emf of battery $=120 \,V$.