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Q.
In the circuit shown in the figure-$3.370$, switch $S$ is closed at time $t=0$. Select the correct statements.
Current Electricity
Solution:
In steady state
$q_{C}=E C $ and $ q_{2 C}=2 EC$
Time constant is same for both the circuits $\tau_{C}=2 RC$.
At time $t$ charge on the two capacitors is given as
$q_{C}=E C\left(1-e^{t / \tau}\right)$
$q_{2 C}=2 E C\left(1-e^{t / \tau}\right)$
$\Rightarrow \frac{q_{C}}{q_{2 C}}=\frac{1}{2}$