Thank you for reporting, we will resolve it shortly
Q.
In the circuit shown in figure potential difference between points $A$ and $B$ is $16\, V$. the current passing through $2\Omega $resistance will be
$\therefore 4 i+2\left(i_{1}+i_{2}\right)-3+4 i_{1}=16\, V$...(i)
Using Kirchhoff's second law in the closed loop we have
$9-i_{2}-2\left(i_{1}+i_{2}\right)=0$ ...(ii)
Solving equations (i) and (ii), we get
$i_{1}=1.5\,A$ and $i_{2}=2\, A$
$\therefore $ current through $2\, W$
resistor $=2+1.5=3.5\, A$
