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Q. In the circuit shown in figure, if the diode forward voltage drop is $0.3 \,V$, the voltage difference between $A$ and $B$ is
image

Semiconductor Electronics: Materials Devices and Simple Circuits

Solution:

Let $V$ be the potential difference between $A$ and $B$, then
$V - 0.3 = (5 + 5) \times 10^3\times (0.2\times 10^{-3}) = 2$
or $V= 2 + 0.3 = 2.3 \,V$