Question

In the circuit shown in figure. If the diode forward voltage drop is $0.3\, V$, the voltage difference between $A$ and $B$ is

• A. 1.3 V
• B. 2.3 V
• C. 0
• D. 0.5 V

Answer 1

Answer: (B)

Let $V$ be the potential difference between $A$ and $B$.
Then $V-0.3 =(5+5) \times 10^{3} \times\left(0.2 \times 10^{-3})=2\right.$
or $V =2+0.3=2.3\, V$