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Q.
In the circuit shown in figure, find the current through the branch $BD$ :
NTA AbhyasNTA Abhyas 2020
Solution:
In loop $ABCD$ by $KVL$ $-6i_{1}-3i_{2}+15=0$ or $2i_{1}+i_{2}=5...\left(\right.1\left.\right)$
in $1000BCDB$
$-3\left(i_{1} - i_{2}\right)-30+3i_{2}=0$
$-i_{1}+2i_{2}=10\ldots \left(\right. 2 \left.\right)$
from $\left(eq\right)^{n}\left(\right.1\left.\right)&\left(\right.2\left.\right)i_{2}=5A$
