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  4. In the circuit shown in figure current in the circuit is

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Q. In the circuit shown in figure current in the circuit isPhysics Question Image

Alternating Current

Solution:

Current in the circuit is
$I = \frac{V_{R}}{R} = \sqrt{\frac{V^{2}-\left(V_{L}-V_{C}\right)^{2}}{R}}$
$= \sqrt{\frac{\left(400 \,V\right)^{2} āˆ’ \left(300 \,Vāˆ’ 200\,V \right)^{2}}{100\,\Omega}} = 3.87\,A$