Question

In the circuit shown in figure-$3.345$ the capacitor of capacitance $C$ is charged to a potential difference $V$. The current in the circuit just after the closing of switch $S$ is :

• A. $\frac{V}{3 R}$
• B. $\frac{3 V}{R}$
• C. $\frac{V}{2 R}$
• D. zero

Answer 1

Answer: (A)

SJust after closing the switch, uncharged capacitor behave like short circuit and charged capacitor behave like an ideal battery so current in circuit is given as
$i=\frac{V}{3 R}$