Q.
In the circuit shown, current flowing through $25\, V$ cell is
Solution:
Applying $KVL$ in loop $ABCDA, ABFEA, ABGHA$ and $ABJIA$,
we get
$30- i _{1} \times 11=-25 \ldots$ (i)
$20+i_{2} \times 5=25 $... (ii)
$5-i_{3} \times 10=-25 \ldots$ (iii)
$10+i_{4} \times 5=25 $... (iv)
Solving equations (i), (ii), (iii) and (iv) we get
$i _{1}=5 \,A , i _{2}=1 \,A , i _{3}=3\, A$ and $i _{4}=3\, A$
Hence, current flowing through $25 \,V$ cell is $12\, A$.
