Question

In the circuit shown, charge on the $5 \mu F$ capacitor is :

• A. $5.45\, \mu C$
• B. $16.36\, \mu C$
• C. $10.90\, \mu C$
• D. $18.00\, \mu C$

Answer 1

Answer: (B)

Now, using junction analysis
We can say, $ q _{1}+ q _{2}+ q _{3}=0$
$2(x-6)+4(x-6)+5(x)=0 $
$x=\frac{36}{11} q_{3}=\frac{36(5)}{11}=\frac{180}{11} $
$q_{3}=16.36 \mu C$