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Q. In the circuit shown below, the cell is ideal,
image
with emf $=2\, V$. The resistance of the coil of the galvanometer $G$ is $1 \,\Omega$. Then
(1) $0.2 \,A$ current flows in $G$
(2) potential difference across $C_{1}$ is $1\, V$
(3) potential difference across $C_{2}$ is $1.2 \,V$
(4) no current flows in $G$

BHUBHU 2007

Solution:

Disregard the capacitors and find the current through $G$. The potential difference across each capacitor is then found from the potential difference across the resistances in parallel with them.