Question

In the circuit shown below $C_{1}=10 \,\mu F , C_{2}=C_{3}=20 \,\mu F$, and $C_{4}=40 \,\mu F$. If the charge on $C_{1}$ is $20 \,\mu C$ then potential difference between $X$ and $Y$ is

• A. 2 V
• B. 3 V
• C. 6 V
• D. 3.5 V

Answer 1

Answer: (B)

$q_{3}=20 \,\mu C$
$q_{4}=q_{4}=40\, \mu C$
$\Delta V=\frac{20}{10}+\frac{20}{20}=3\, V$