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Q. In the circuit $R_1 = R_2$.The value of $E$ and $R_1$ are ________($E-EMF,R_1$-resistance)Physics Question Image

KCETKCET 2013Current Electricity

Solution:

Applying Kirchoff's 2 nd law in loop $A B E F A$
$-I R-(I-1.5) R+E=0$
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or $ E=I R+(I-1.5) R$
$\Rightarrow E=R[2 /-1.5] \,\,\,\,\,\,...(i)$
Now apply KVL in loop $ABCDEFA$, $-I R-1.5 R'+E=0$
$\Rightarrow E=I R+1.5 R'\,\,\,\,\,\,\,...(ii)$
Eliminating / from Equ. (i) and (ii),
$\Rightarrow \frac{1}{2}\left[\frac{E}{R}+1.5\right]=1\,\,\,\,\,$[from Eq.(i)]
and $\left[\frac{E-1.5 R^{\prime}}{R}\right]=1$
[from Eq. (ii)]
So, $\frac{E}{R}+1.5=\frac{2}{R}\left[E-1.5 R'\right]$
So, if $R'$ were known, then from options we could get the answer.