Question

In the circuit of the figure, the source frequency is $\omega=2000\, rad \,s ^{-1}$. The current in the circuit will be

• A. $2 \,A$
• B. $3.3 \, A$
• C. $2 / \sqrt{5} \, A$
• D. $\sqrt{5} \, A$

Answer 1

Answer: (A)

$X_{L}=L \omega=5 \times 10^{-3} \times 2000=10 \,\Omega $
$X_{C}=\frac{1}{C \omega}=\frac{1}{50 \times 10^{-6} \times 2000}$
$=\frac{100}{10} \Omega=10\, \Omega$
Since $X_{ L } =X_{ C }, $ therefore
$Z =R=5.9+0.10+4=10 \,\Omega$
$I_{ v } =\frac{E_{ v }}{Z}=\frac{20}{10} A =2 \,A$