Thank you for reporting, we will resolve it shortly
Q.
In the circuit, given in the figure currents in different branches and value of one resistor are shown. Then potential at point $B$ with respect to the point $A$ is :
Let us asssume the potential at $A = V _{ A }=0$
Now at junction $C$, According to $KCL$
$i _{1}+ i _{3}= i _{2}$
$1 A + i _{3}=2 A$
$i_{3}=2 A$
Now Analyse potential along ACDB
$v _{ A }+1+ i _{3}(2)-2= v _{ B }$
$0+1+2(1)-2=v_{B}$
$v _{ B }=3-2$
$v _{ B }=1$ Volt
